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Beginning Algebra
Answer/Discussion to Practice Problems
Tutorial 21: Graphing Linear Equations



 

checkAnswer/Discussion to 1a

y = 2x - 1


 
If we subtract 2x from both sides, then we can write the given equation as -2x + y = -1. 

Since we can write it in the standard form, Ax + By = C, then we have a linear equation. 

(return to problem 1a)


 


 

checkAnswer/Discussion to 1b

problem 1b


 
If we add x squared to both sides we would end up with ad1b.   Is this a linear equation?  Note how we have an x squared as opposed to x to the one power. 

It looks like we cannot write it in the form Ax + By = C, because the x has to be to the one power, not squared.  So this is not a linear equation. 

(return to problem 1b)


 


 

checkAnswer/Discussion to 2a

 y = 2x - 1


 

The three x values I'm going to use are -1, 0, and 1.  (Note that you can pick ANY three x values that you want.  You do not have to use the values that I picked.) You want to keep it as simple as possible.  The following is the chart I ended up with after plugging in the values I mentioned for x.
 
 

x
y = 2x - 1
(x, y)
-1
y = 2(-1) - 1 = -3
(-1, -3)
0
y = 2(0) - 1 = -1
(0, -1)
1
y = 2(1) - 1 = 1
(1, 1)

 

ad2a1


 
 
Step 3:  Draw the graph.

ad2b1

(return to problem 2a)


 


 

checkAnswer/Discussion to 2b

problem 2b


 

The three x values I'm going to use are -1, 0, and 1.  (Note that you can pick ANY three x values that you want.  You do not have to use the values that I picked.) You want to keep it as simple as possible.  The following is the chart I ended up with after plugging in the values I mentioned for x.
 
 

x
y = -1/2x
(x, y)
-1
y = -1/2(-1) = 1/2
(-1, 1/2)
0
y = -1/2(0) = 0
(0, 0)
1
y = -1/2(1) = -1/2
(1, -1/2)

 

ad2b1


 
 
Step 3:  Draw the graph.

ad2b2

(return to problem 2b)


 

 

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Last revised on July 29, 2011 by Kim Seward.
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