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Answer/Discussion to 1a

 

*Inverse of sub. 1/5 is add. 1/5

 

If you put 4/5 back in for x in the original problem you will see that 4/5 is the solution to our problem.

 

(return to problem 1a)

 

 

Answer/Discussion to 1b

 

*Inverse of add 7 is sub. 7

 

If you put -9 back in for b in the original problem you will see that -9 is the solution to our problem.

 

(return to problem 1b)

 

 

Answer/Discussion to 1c

 

*Inverse of sub. .5x is add .5x *Inverse of sub. 7.1 is add 7.1

 

If you put 5.9 back in for x in the original problem you will see that 5.9 is the solution to our problem.

 

(return to problem 1c)

 

 

Answer/Discussion to 1d Using the distributive property and then combining like terms to simplify the left side of the equation we get:

 

*Use distributive prop. *Combine like terms

 

Solving for x we get:

 

*Inverse of add x is sub. x   *Inverse of add 13 is sub. 13

 

If you put -15 back in for x in the original problem you will see that -15 is the solution to our problem.

 

(return to problem 1d)

 

 

Answer/Discussion to 2a Two numbers have a sum of 200.  If one number is x, express the other number in terms of x.

 

Since our total is 200 and we are letting x represent one number, the other number would be expressed as the total minus x or 200 - x. So, 200 - x is our answer.

 

(return to problem 2a)

 

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Last revised on July 26, 2011 by Kim Seward.
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